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Work done by Constant Force

  1. Oct 19, 2009 #1
    A cable lifts a 1260-kg elevator at a constant velocity for a distance of 42.3 m. What is the work done by (a) the tension in the cable and (b) the elevator's weight?

    For part a.) w=(Fcos(theta))s
    w=(fcos(0))s
    =fs and s= 42.3

    part b.) Fcos(theta))s
    w=(fcos(180)s
    =-fs and s= 42.3
    BUt how do i find F??? and is this the right set up??
     
  2. jcsd
  3. Oct 19, 2009 #2

    turin

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    How did you find theta in each case? In order for you to decide what is theta, should should have had an idea what was the F.
     
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