A cable lifts a 1260-kg elevator at a constant velocity for a distance of 42.3 m. What is the work done by (a) the tension in the cable and (b) the elevator's weight? For part a.) w=(Fcos(theta))s w=(fcos(0))s =fs and s= 42.3 part b.) Fcos(theta))s w=(fcos(180)s =-fs and s= 42.3 BUt how do i find F??? and is this the right set up??