1. The problem statement, all variables and given/known data 2. Relevant equations W = fdcos∅ 3. The attempt at a solution I know how to solve the problem using potential energy (i.e. mgh) and the answer is 4.41 J. My question is, how do I solve it using the work done by the applied force using fdcos∅? The work done parallel to the incline is 82sin(53) = 65.49 The distance the the box moves up the incline when h = .15 is (I think), .15cos(53) = .09027. However, when multiplying them together (.09027*65.49) I get 5.9 J. What am I doing wrong? I'm pretty sure it's in finding the distance that the box travels up the incline. -edit- I see what I'm doing wrong and it is in the distance the box travels up. I need the angle of the incline, not the force to ground. Is there any way to find that angle?