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Work done by force

  1. Dec 13, 2013 #1
    1. The problem statement, all variables and given/known data

    A particle moves only along the x-axis, and is subject to a force towards the origin of magnitude kx^3. if the particle moves from x1 to x2 how much work does this force do on it? (consider the case x1<x2)

    2. Relevant equations

    W=Fd

    3. The attempt at a solution

    kx^3(x2-x1)
     
  2. jcsd
  3. Dec 13, 2013 #2
    I just noticed that the force would change as the particle moved along the x-axis. Taking the anti-derivative of kx^3 from x1 to x2 I got (kx2^4)/4 - (kx1^4)/4 = k/4 (x2^4-x1^4)
     
  4. Dec 13, 2013 #3
    Looking good to me!
     
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