Problem. Find Work done by each path. My Solution. a-b, c-d >> W=P(delta)V a-c, b-d >> W=0 My Question. What is the work done by the gas (path a-d)? My Thoughts. There is a change in both pressure and volume. However, the equation to find the work in this situation is "W=P(delta)V". There is no (delta)P.
Are you familiar with integration? The answer is always found by calculating the area under the curve, which is exactly what you did for all the other ones. In this case, the area is a trapezoid
so the work done from a to d is W = deltaP * deltaV very good, P is no longer constant so integrate that as well as if it was that simple