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Homework Help: Work Done by Gas PV Diagram

  1. Jan 24, 2007 #1
    http://img294.imageshack.us/img294/8068/pvdiagram2fo.gif [Broken]
    Find Work done by each path.

    My Solution.
    a-b, c-d >> W=P(delta)V
    a-c, b-d >> W=0

    My Question.
    What is the work done by the gas (path a-d)?

    My Thoughts.
    There is a change in both pressure and volume. However, the equation to find the work in this situation is "W=P(delta)V". There is no (delta)P.
    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. Jan 25, 2007 #2
    could anyone help him?I'm kinda interested in the answer to this as well!
    Last edited: Jan 25, 2007
  4. Jan 25, 2007 #3
    Are you familiar with integration? The answer is always found by calculating the area under the curve, which is exactly what you did for all the other ones. In this case, the area is a trapezoid
  5. Jan 25, 2007 #4
    so the work done from a to d is W = deltaP * deltaV
    very good, P is no longer constant so integrate that as well
    as if it was that simple
    Last edited: Jan 25, 2007
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