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Work Done by Gas PV Diagram

  • Thread starter Malicious
  • Start date
16
0
Problem.
http://img294.imageshack.us/img294/8068/pvdiagram2fo.gif [Broken]
Find Work done by each path.

My Solution.
a-b, c-d >> W=P(delta)V
a-c, b-d >> W=0

My Question.
What is the work done by the gas (path a-d)?

My Thoughts.
There is a change in both pressure and volume. However, the equation to find the work in this situation is "W=P(delta)V". There is no (delta)P.
 
Last edited by a moderator:

Answers and Replies

20
0
could anyone help him?I'm kinda interested in the answer to this as well!
 
Last edited:
312
0
Are you familiar with integration? The answer is always found by calculating the area under the curve, which is exactly what you did for all the other ones. In this case, the area is a trapezoid
 
20
0
so the work done from a to d is W = deltaP * deltaV
very good, P is no longer constant so integrate that as well
as if it was that simple
 
Last edited:

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