sicjeff said:W/mole = dPV = Pdv + Vdp.
it should be pretty obvious from here.
sicjeff said:okay, I assume you are in like a freshman/sophmore level physics course right.
Let's assume an ideal gas.
we know the standard molar volume right? (22.414 L/mole). so v=nRT/P.
We are assuming that the size of our container is constant. (isochoric condition)
The question does not have sufficient information. You have to know how the pressure is changed and whether heat is being added or released.Tehy said:Hello! Any ideas how I could solve this exercise:
5 mol of gas is in temperature of 326K and the same time the pressure is expanded from 1atm to 3atm. How much work is done by the gas?
Detailed instruction would be good, thanks :)
The work done by a gas can be calculated using the formula: W = PΔV, where W is the work done, P is the pressure, and ΔV is the change in volume of the gas.
The unit of measurement for work done by a gas is joules (J). However, in some cases, it may also be measured in other units such as calories or kilogram-force meters (kgf·m).
Yes, the work done by a gas is a signed quantity and depends on the direction of expansion or compression. If the gas expands, the work done will be positive, whereas if the gas is compressed, the work done will be negative.
Yes, the work done by a gas can be zero if there is no change in volume or pressure. This can happen when the gas is in a state of equilibrium, where the external pressure is equal to the internal pressure of the gas.
The work done by a gas is directly related to its internal energy. When work is done on a gas, its internal energy increases, and when work is done by a gas, its internal energy decreases. This is known as the first law of thermodynamics.