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Work done by melting ice

  • Thread starter cashmerelc
  • Start date
18
0
Okay, if you have 1 kilomole of ice melting at 0 C and you have a given latent heat of fusion of ice as 3.348 x 10^5 J/kg and the density of ice as 917 kg/m^3 and te density of water as 999.9 kg/m^3, I don't understand how to find the work done.

I know that work done is PdV, so it should be W=P(V2-V1).

I understand that the volumes is the mass in kg of the water molecules over the densities of ice and water. But how do you solve P?

P=nRT/V. so P = (1 kilomole)(8.314 x 10^3 j/kK)(273 K)/V.

I don't really understand how to solve for V.
 

Answers and Replies

Mapes
Science Advisor
Homework Helper
Gold Member
2,592
17
There's only one pressure where ice melts at 0°C. You're not really trying to bring the ideal gas law into a question about a solid and a liquid, are you?
 
18
0
1 atm?
 

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