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Work done by melting ice

  1. Mar 21, 2008 #1
    Okay, if you have 1 kilomole of ice melting at 0 C and you have a given latent heat of fusion of ice as 3.348 x 10^5 J/kg and the density of ice as 917 kg/m^3 and te density of water as 999.9 kg/m^3, I don't understand how to find the work done.

    I know that work done is PdV, so it should be W=P(V2-V1).

    I understand that the volumes is the mass in kg of the water molecules over the densities of ice and water. But how do you solve P?

    P=nRT/V. so P = (1 kilomole)(8.314 x 10^3 j/kK)(273 K)/V.

    I don't really understand how to solve for V.
  2. jcsd
  3. Mar 21, 2008 #2


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    There's only one pressure where ice melts at 0°C. You're not really trying to bring the ideal gas law into a question about a solid and a liquid, are you?
  4. Mar 21, 2008 #3
    1 atm?
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