How Much Work Does a Non-Ideal Gas Perform During Expansion?

In summary, the problem asks for the amount of work done by a non-ideal monatomic gas as it expands from Vi = 0.3 m3 to Vf = 0.44 m3 at T = 100 K. The relation between pressure and volume for this gas is given by P = Po(Vo/V)1/2, where To = 100 K, Po = 100000 Pa, and Vo = 0.1 m3. To solve this problem, the definition of work done by a gas can be used.
  • #1
ODrule
1
0

Homework Statement



For some particular unusual non-ideal monatomic gas, take the relation beween P and V at some fixed To to be
P = Po(Vo/V)1/2.
Let To = 100 K, Po = 100000 Pa, and Vo = 0.1 m3.

Homework Equations



How much work does this gas do if it expands, pushing on a piston, from Vi = 0.3 m3 to Vf = 0.44 m3 at T = 100 K?

The Attempt at a Solution



Someone please help?
I don't understand non-ideal gases.
 
Physics news on Phys.org
  • #2
Even though you don't know much about non-ideal gases, that doesn't mean you can't do anything here. Give me some of your thoughts on the problem. Here's a hint to get you started thinking:

What is the definition of work done by a gas? This should still apply to this non-ideal gas, correct?
 
  • #3


I would first clarify the concept of non-ideal gases. Non-ideal gases are gases that do not follow the ideal gas law, which states that the pressure, volume, and temperature of a gas are directly proportional to each other. Non-ideal gases deviate from this law due to factors such as intermolecular interactions, volume occupied by the molecules, and non-uniformity of the gas.

In this problem, we are given a specific non-ideal gas with a relationship between pressure and volume at a fixed temperature. This relationship is given by the equation P = Po(Vo/V)^(1/2), where Po is the initial pressure, Vo is the initial volume, and V is the final volume.

To calculate the work done by this gas, we can use the formula W = P(Vf - Vi), where W is the work done, P is the pressure, and Vf and Vi are the final and initial volumes, respectively.

Substituting the given values, we get W = 100000((0.44)^1/2 - (0.3)^1/2) = 6175.5 Joules.

Therefore, the work done by this non-ideal gas as it expands from 0.3 m3 to 0.44 m3 at 100 K is 6175.5 Joules. This value may be different from the work done by an ideal gas in the same conditions, highlighting the non-ideal behavior of this gas.
 

1. What is the definition of work done by a non-ideal gas?

The work done by a non-ideal gas is the measure of the force exerted by the gas on its surroundings as it expands or contracts. This work is typically calculated using the pressure-volume (PV) curve on a graph.

2. How does the work done by a non-ideal gas differ from an ideal gas?

An ideal gas is one that follows the ideal gas law, which assumes that the gas particles have no volume and do not interact with each other. In reality, most gases are non-ideal, meaning they have volume and do interact with each other, resulting in a different PV curve and thus a different amount of work done.

3. What factors affect the work done by a non-ideal gas?

The work done by a non-ideal gas is affected by the pressure, volume, and temperature of the gas. It also depends on the type of gas and the conditions under which it is expanding or contracting.

4. How is the work done by a non-ideal gas calculated?

The work done by a non-ideal gas is calculated by finding the area under the PV curve on a graph. This can be done using calculus or by using a numerical integration method.

5. What are some real-world applications of understanding work done by non-ideal gases?

Understanding the work done by non-ideal gases is important in various fields such as chemistry, engineering, and thermodynamics. It can be used to design more efficient engines, predict the behavior of gases in different conditions, and develop better gas storage and transportation systems.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
844
  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
11
Views
3K
  • Introductory Physics Homework Help
Replies
17
Views
2K
  • Introductory Physics Homework Help
Replies
21
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
3K
Replies
22
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
1
Views
794
  • Introductory Physics Homework Help
Replies
9
Views
1K
Back
Top