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Work done by spring

  • Thread starter mochabcha
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  • #1
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I have a problem I need help with:
A block lies on a horizontal frictionless surface and is attached to the free end of the spring, with a spring constant of 35 N/m. Initially, the spring is at its relaxed length and the block is stationary at position x = 0. Then an applied force with a constant magnitude of 2.8 N pulls the block in the positive direction of the x axis, stretching the spring until the block stops.
Assume that the stopping point is reached. What is the position of the block?
 

Answers and Replies

  • #2
Gokul43201
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What's the problem with the problem ? Draw a force diagram. You know how to calculate the force due a stretched spring...do it.
 
  • #3
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I've tried the formula F(spring) = -kx and got -.08 but thats not the answer.

It seems to me when the mass stops the applied force will equal the spring force
 
  • #4
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next time try posting in the homework help section
 
  • #5
Gokul43201
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And check your sign. Read what the question says about which direction (positive or negative x-direction) the block is pulled.
 

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