Work done by the magnetic field on the resistor

In summary, both statements (a) and (b) are valid during the time the resistor is falling at terminal velocity.
  • #1
syhpui2
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Homework Statement



A magnetic field, B= 0.8 T, is directed out of the page in a region containing a rectangular up-side-down "U-wire" having width W = 0.5 m, as shown. A resistor of mass m and resistance R = 6 Ω, which is free to slide without friction on the vertical rails, is released from rest and starts falling in the presence of the Earth's gravitational field, reaching a terminal speed v = 3.8 m/s.

ukw8m.png


http://i.imgur.com/ukw8m.png


Which statement(s) below is (are) valid during the time the resistor is falling at terminal velocity?

(a) The work per unit time done by the Earth on the resistor is equal to the power dissipated in the resistor.

(b) The work done by the magnetic field on the resistor is equal in magnitude, but opposite in sign, to the work done by the Earth on the resistor.

(c) Both of the statements above are valid.



Correct Answer: C



Homework Equations



P=UI

The Attempt at a Solution



I tried to analyze with P=UI. However, I get answer B. Should I analyze it with W=Fd?
 
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  • #2


it is important to consider both the equations and the physical concepts involved in a problem. In this case, both P=UI and W=Fd can be used to analyze the situation.

Using P=UI, we can see that the power dissipated in the resistor is equal to the work done by the Earth on the resistor. This is because the power dissipated in the resistor is equal to the product of the current (I) and voltage (U), which is also equal to the rate at which energy is transferred by the Earth's gravitational field to the resistor as it falls. Therefore, statement (a) is valid.

Using W=Fd, we can see that the work done by the magnetic field on the resistor is equal in magnitude, but opposite in sign, to the work done by the Earth on the resistor. This is because the magnetic force on the resistor is perpendicular to the direction of motion, and therefore does no work. Instead, the work done by the magnetic field is in the form of changing the direction of the resistor's motion, which is opposite to the work done by the Earth's gravitational field. Therefore, statement (b) is also valid.

In conclusion, both statements (a) and (b) are valid during the time the resistor is falling at terminal velocity. It is important for scientists to consider both the equations and physical concepts involved in a problem to fully understand and analyze a situation.
 

1. What is work done by the magnetic field on the resistor?

The work done by the magnetic field on the resistor refers to the amount of energy transferred to the resistor by the magnetic field. This energy is converted into heat, which causes the resistor to dissipate energy and perform its intended function in an electrical circuit.

2. How is work done by the magnetic field on the resistor calculated?

The work done by the magnetic field on the resistor is calculated using the formula W = BILcosθ, where B is the strength of the magnetic field, I is the current flowing through the resistor, L is the length of the resistor, and θ is the angle between the magnetic field and the direction of current flow.

3. Is work done by the magnetic field on the resistor positive or negative?

The work done by the magnetic field on the resistor can be either positive or negative, depending on the direction of the magnetic field and the direction of current flow. If the magnetic field and current flow are in the same direction, the work done is positive. If they are in opposite directions, the work done is negative.

4. Can the work done by the magnetic field on the resistor be zero?

Yes, the work done by the magnetic field on the resistor can be zero if the magnetic field and current flow are perpendicular to each other (θ = 90 degrees). In this case, the cosine of θ is zero, making the work done also zero.

5. How does the work done by the magnetic field on the resistor affect the resistance?

The work done by the magnetic field on the resistor does not directly affect the resistance. However, it does contribute to the heating of the resistor, which can cause an increase in resistance. This is known as the Joule effect and is an important consideration in circuit design to prevent overheating and damage to components.

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