How Much Work Do Each of the Forces Do on the Crate?

[DRC12]

Homework Statement

The three ropes shown in the bird's-eye view of the figure (Figure 1) are used to drag a crate 3.2 across the floor.How much work is done by each of the three forces? Then the picture is Force one is 600N 20^o above the x-axis force two is 410N 30^o below the x-axis and force 3 is 650N along the x-axis in the negative direction

Homework Equations

w=Fscos(∂)

The Attempt at a Solution

So I plugged the each of the numbers into the equation and got work from force one to be 600*3.2*cos20=1804J, the work from force two to be 410*3.2*cos30=1136 and work from force three equals 650*3.2*cos180=-2080
This seems really easy but when I plug it into the website it says it's wrong and gives no feedback I can't figure out what I'm doing wrong

 

[Doc Al]

This seems really easy but when I plug it into the website it says it's wrong and gives no feedback I can't figure out what I'm doing wrong

Your work looks good to me. Sometimes they are fussy about the number of significant figures.

 

[DRC12]

This site doesn't care about significant figures but it tends to be unclear about what it's looking for I just wanted to make sure I wasn't making any small mistakes

 

[DRC12]

Just realized I was supposed to answer in kJ instead of J

 

[Nickie]

.

As a scientist, it is important to carefully analyze the problem and make sure all factors are considered. In this case, the work done by each force should be calculated using the formula W = Fcos(θ)d, where θ is the angle between the force and the displacement of the crate, and d is the distance the crate is dragged.

From the given information, it seems that the angles given for force one and two are not the angles between the forces and the displacement of the crate, but rather the angles with respect to the x-axis. To find the angle between the forces and the displacement, we can use trigonometric identities and the given angles to find the angles between the forces and the displacement.

For force one, the angle between the force and the displacement can be found by using the angle of 20 degrees and the given angle of 30 degrees below the x-axis. This gives us an angle of 50 degrees between the force and the displacement.

Similarly, for force two, the angle between the force and the displacement can be found by using the angle of 30 degrees and the given angle of 20 degrees above the x-axis. This gives us an angle of 50 degrees between the force and the displacement.

Using these new angles, the work done by each force can be calculated as follows:

Work done by force one = 600 * 3.2 * cos(50) = 1922.1 J
Work done by force two = 410 * 3.2 * cos(50) = 1317.6 J
Work done by force three = 650 * 3.2 * cos(180) = -2080 J

Therefore, the total work done by the three forces is 1922.1 + 1317.6 - 2080 = 1160.7 J.

It is important to carefully consider all factors and double check calculations to ensure accuracy in scientific work.