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## Homework Statement

The three ropes shown in the bird's-eye view of the figure (Figure 1) are used to drag a crate 3.2 across the floor.How much work is done by each of the three forces? Then the picture is Force one is 600N 20

^{o}above the x-axis force two is 410N 30

^{o}below the x-axis and force 3 is 650N along the x-axis in the negative direction

## Homework Equations

w=Fscos(∂)

## The Attempt at a Solution

So I plugged the each of the numbers into the equation and got work from force one to be 600*3.2*cos20=1804J, the work from force two to be 410*3.2*cos30=1136 and work from force three equals 650*3.2*cos180=-2080

This seems really easy but when I plug it into the website it says it's wrong and gives no feedback I can't figure out what I'm doing wrong