Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Work done in a reversible adiabatic change

  1. Nov 6, 2004 #1
    Can anyone help me with this?


    Show that the work done in a reversible adiabatic change from an initial state (p1, V1) to a final state (p2, V2) is:

    W = ( p2V2 - p1V1) / (gamma - 1)


    Here's what (little) I have done so far:

    Reversible => dW = -pdV
    Adiabatic => dq = 0
    gamma = Cp/Cv

    I know pV^gamma = constant, so p1V1^gamma = p2V2^gamma
    Last edited: Nov 6, 2004
  2. jcsd
  3. Nov 6, 2004 #2


    User Avatar
    Science Advisor
    Gold Member

    As you stated, you have P(V) as an adiabatic process.

    The only thing you have to do is to substitute P(V) in the integral of work, and solve the integral.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook