Can anyone help me with this?(adsbygoogle = window.adsbygoogle || []).push({});

--

Show that the work done in a reversible adiabatic change from an initial state (p1, V1) to a final state (p2, V2) is:

W = ( p2V2 - p1V1) / (gamma - 1)

--

Here's what (little) I have done so far:

Reversible => dW = -pdV

Adiabatic => dq = 0

gamma = Cp/Cv

I know pV^gamma = constant, so p1V1^gamma = p2V2^gamma

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Work done in a reversible adiabatic change

**Physics Forums | Science Articles, Homework Help, Discussion**