- #1

frozen7

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When lift up the box to 2m forward. Find out the work done by the gravitational force.

I find it by W = mg (x)

But my lecturer encourage me to do it in this way: W = 2mgsin(a), and told me that my method is correct in trigonometric but not really correct in physics.

I would like to know whether my method is really not suitable or it is correct actually?

I find it by W = mg (x)

But my lecturer encourage me to do it in this way: W = 2mgsin(a), and told me that my method is correct in trigonometric but not really correct in physics.

I would like to know whether my method is really not suitable or it is correct actually?