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bigtymer8700
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[SOLVED] Work done on box
An 8.00kg package in a mail-sorting room slides 2.00m down a chute that is inclined at 53.0 below the horizontal. The coefficient of kinetic friction between the package and the chute's surface is 0.400.
its asking me for the work done on the package by gravity and then the net work done on the package. wouldn't the work by gravity just be the weight. and for the normal force i just subtracted the frictional force from the normal force. where am i messing up?
W= F cos(53) s
Friction Force= .4(Fnormal)
I already figured out the frictional force to be 37.7 and the force 94J.
Homework Statement
An 8.00kg package in a mail-sorting room slides 2.00m down a chute that is inclined at 53.0 below the horizontal. The coefficient of kinetic friction between the package and the chute's surface is 0.400.
its asking me for the work done on the package by gravity and then the net work done on the package. wouldn't the work by gravity just be the weight. and for the normal force i just subtracted the frictional force from the normal force. where am i messing up?
Homework Equations
W= F cos(53) s
Friction Force= .4(Fnormal)
The Attempt at a Solution
I already figured out the frictional force to be 37.7 and the force 94J.
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