A block is being slid along a rough surface by a force of 94.6 N forming an upward angle with the horizontal of 29 degrees. The mass of the block is 18.7 kg. It is displaced 70.6 m, and the coefficient of friction is .186
what is the total work done by the force.
Work = (Fnet)(displacement)
friction = coefficient(Fnormal)
The Attempt at a Solution
I drew a free body diagram, and derived these equations:
Fnormal + 94.6sin(29) = mg
Fnet = 94.6cos(29) - friction
From this, I got that Fnormal = 137.3970099 N
friction = 25.55584385 N
Fnet = 57.18318045 N
thus, 57.18318045 N x 70.6 m = 4037.13254 J
Our online program for homework is telling me this is incorrect >.< I'm really not sure what to do.