To push a 25.0 kg crate up a frictionless incline, angled at 25.0 degrees to the horizontal, a worker exerts a force of 209N parallel to the incline. As the crate slides 1.50m, how much work is done on the crate by the worker's applied force?(adsbygoogle = window.adsbygoogle || []).push({});

I know that W=d x F(cos(angle))

Why doesn't it work when I use (1.50m)(209N)(Cos(25)) = 284 J

Answer is supposed to be 314 J. Is the angle used in the equation supposed to be 0 because the force is parallel to the incline? If the force was parallel to the x axis, would you then use Cos (25)? Just want to make sure I'm understanding this.

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# Work done to an object

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