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Work done

  1. Nov 8, 2006 #1
    untitled.GIF
    the question is what is the work done by F on the ball
    so this is what i did
    since F is constant we can apply
    untitled2.GIF
    and now here's my question, does the work done in this case depends on the path (curve) or the displacement (straight line)?
     
    Last edited: Nov 8, 2006
  2. jcsd
  3. Nov 8, 2006 #2
    untitled.GIF
    so i'm trying to find the work done by F on the ball

    and this is what i got
    texserver.gif
    where
    sqrt(2LH) is the displacement from the bottom to the position with height H.

    So, i'm just wondering if this is correct or i'm missing something
     
    Last edited: Nov 8, 2006
  4. Nov 8, 2006 #3

    Doc Al

    User Avatar

    Staff: Mentor

    It depends on the component of the displacement in the direction of the force. (Read up on the meaning of the scalar/dot product of two vectors.)
     
  5. Nov 10, 2006 #4
    it depenson dsplacement....kinectic converted into gravitational
     
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