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Work Done

  1. Jun 2, 2005 #1
    Hi mates.

    I was doing a practice exam and I came across an interesting question.
    Calculate the work done accelerating a proton to a speed of [tex]6.00*10^7 ms^-1[/tex] from rest.

    Proton mass [tex]=[/tex] [tex]1.67*10^-27[/tex]

    How would I go about solving it?
     
  2. jcsd
  3. Jun 2, 2005 #2
    It will just be the kinetic energy of the proton when it has that speed (since it started from rest).
     
  4. Jun 2, 2005 #3
    thank you mate :)
     
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