- #1
jinx007
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A constant force of 9 kN parallel to an inclined plane, moves a body of weight 20 kN through a distance of 40m along a plane at a constant speed. The body gains 12 m height..
HOW MUCH WORK IS DISSIPATED AS HEAT?
A/ 120 KJ
B/ 240 KJ
C/ 360 KJ
D/ 600 KJ
So workdone = f x d
but i am a bit confuse as the question say the heat dissipated
so i think that the work done = 20 kN X 12 = 240 KN (heat dissipated) answer
However the work done is 9 KN X 40 = 360 KJ
AM I ON THE RIGHT TRACK ? HELP BY THE WAY ACCORDING TO ME THE ANSWER IS B
HOW MUCH WORK IS DISSIPATED AS HEAT?
A/ 120 KJ
B/ 240 KJ
C/ 360 KJ
D/ 600 KJ
So workdone = f x d
but i am a bit confuse as the question say the heat dissipated
so i think that the work done = 20 kN X 12 = 240 KN (heat dissipated) answer
However the work done is 9 KN X 40 = 360 KJ
AM I ON THE RIGHT TRACK ? HELP BY THE WAY ACCORDING TO ME THE ANSWER IS B