# Work Energy Principle

1. Nov 11, 2007

### shakejuhn

1. The problem statement, all variables and given/known data

You throw a 25.0N rock into the air from ground level and observe that, when it is 13.0m high, it is traveling upward at 21.0m/s

A. Use the work-energy principle to find the rock's speed just as it left the ground.

B. Use the work-energy principle to find the maximum height the rock will reach.

2. Relevant equations

=K.E.i+P.E.i=K.E.f+P.E.f
=.5(m)(vf)^2
=M*g*H

3. The attempt at a solution

so far i got
.5(25*9.8)(21.0)^2 + 0 = 31213
i know this is not rigth how do i use the equations to get the answers

2. Nov 11, 2007

### hage567

Initially, the rock only has kinetic energy. When it is at 13 meters above the ground, it has both gravitational potential energy and kinetic energy. So you will have three terms to use in your conservation of energy equation.

Note: weight = m*g, so if you want to convert Newtons into kg it would be m = w/g, you seem to have it wrong in your work.