- #1

- 3

- 0

## Homework Statement

A 34.0 kg crate is initially moving with a velocity that has magnitude 3.70 m/s in a direction 37.0 degrees west of north. How much work must be done on the crate to change its velocity to 6.08 m/s in a direction 63.0 degrees south of east?

## Homework Equations

W=1/2mvf^2-1/2mvi^2

## The Attempt at a Solution

I attempted this by breaking the velocities into their components and got -2.23m/s in the initial x, 2.95m/s in the initial y, 2.76m/s in the final x, and -5.42m/s in the final y. Then I did the work-energy theorem for both x and y components and got work in x direction to be 44.96J and work in the y direction to be 351.46J. Then I did the Pythagorean theorem to get work to be 354.32J But this is wrong, can anyone help?