problem - a bullet of mass .012kg and horizontal speed 70meters per second strikes a block of mass 0.4 kg and instantly comes to rest with respect to the block. the block is suspended from the ceiling by means of thin wires . calculate the height through which it rises. attempt - total initial energy = 1/2(mv^2)=1/2*.012*70*70 total final energy = mgh=(0.012+.4)*10*h equating the 2 . i get 7.5 meteres but the answer given is 21.2 cm . pls help .