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a bullet of mass .012kg and horizontal speed 70meters per second strikes a block of mass 0.4 kg and instantly comes to rest with respect to the block. the block is suspended from the ceiling by means of thin wires . calculate the height through which it rises.

attempt -

total initial energy = 1/2(mv^2)=1/2*.012*70*70

total final energy = mgh=(0.012+.4)*10*h

equating the 2 .

i get 7.5 meteres but the answer given is 21.2 cm .

pls help .

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# Homework Help: Work energy theorem question

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