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## Homework Statement

Near the surface of the Earth, a block of cheese with mass m lies on the foor of

a elevator cab with mass M = 1,000m (i.e., the mass of the cab is 1,000 times

the mass of the cheese) that is being pulled upward by a cable. If through the

distance d = 2m, the normal force on the block from the floor has constant

magnitude FN = 3N, how much work is done on the cab by the force from the

cable?

## Homework Equations

W = fd

F = ma

## The Attempt at a Solution

The distance moved is two meters, so the only unknown necessary to solve is the force from the cable on the cab.

If you consider the entire system of cheese and elevator,

Fc - mg - 1000mg = 1001ma

Just the cheese,

3 - mg = ma

a = 3/m - g

Combine the two,

Fc = 1001mg + 1001m(3/m - g)

Fc = 1001mg + 3003 - 1001mg

Fc = 3003 N

W = (3003N)(2m) = 6,006 J

However, the answer is apparently 6,001 J. Can anyone explain why to me? Or is this a misprint on the answer sheet...