- #1
Ibraheem
- 51
- 2
Hello,
I have been trying to understand why the work in the change of enthalpy equation is canceled out at constant pressure. How can work done by a system equal the work done on the system by atmospheric pressure. For example, when a reaction, taking place in piston-cylinder- like apparatus at standard conditions, releases gas, the piston moves up which means work done by the system.So how can the work done on the system by the atmospheric equals the pressure done by the gas from the reaction if we assume that the piston is mass-less.
I have been trying to understand why the work in the change of enthalpy equation is canceled out at constant pressure. How can work done by a system equal the work done on the system by atmospheric pressure. For example, when a reaction, taking place in piston-cylinder- like apparatus at standard conditions, releases gas, the piston moves up which means work done by the system.So how can the work done on the system by the atmospheric equals the pressure done by the gas from the reaction if we assume that the piston is mass-less.