given curve:(adsbygoogle = window.adsbygoogle || []).push({});

x=cost

y=sin(2t)

z=cos(2t)

0<=t<=2pi

vectorian field:

F=(exp(x^3),3z/(y^2+z^2),-3y/(y^2+z^2))

so the ingral SF*dr (on the curve)

at the direction of t from 0 to 2pi is?

if i assign the parametrion to the field i get 12pi from integrals on y and z

but i still need to proove that the integral there:

https://www.physicsforums.com/showthread.php?t=43059

is zero

and i think its impossible..

i think using stocks is impossible because building sutaible surface to the curve is imposible

any other sugestions?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Work integral on hard field

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**