# WORK-KE help?

## Homework Statement

The 2008 dodge viper srt uses a v-10 engine to develop more than 600HP of the power,

question- If the mass of the viper is 1560 kg, what work must be done by the car to accelerate from rest to 30m/s>

## Homework Equations

I am confused on what formula to use

## The Attempt at a Solution

I did.. KE=1/2mv^2.... so...1/2(1560KG)(30m/s)^2... is this correct?

## Homework Statement

The 2008 dodge viper srt uses a v-10 engine to develop more than 600HP of the power,

question- If the mass of the viper is 1560 kg, what work must be done by the car to accelerate from rest to 30m/s>

## Homework Equations

I am confused on what formula to use

## The Attempt at a Solution

I did.. KE=1/2mv^2.... so...1/2(1560KG)(30m/s)^2... is this correct?

Yes.

Out of interest, what other formulae do you have at your disposal?]

edit: I didn't read your question properly, I do apologise.

this is the energy transfer, not power.

For power there are several equations available:

$$W = F \cdot \Delta d$$

$$P(t) = F(t) \cdot v(t)$$

$$P = \frac{W}{\Delta s}$$

and also remember that horsepower can be converted to SI units of power.

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its a take home quiz... the formulas stated are... KE, PE, work, power and %lost

i was hesitant because Joules obtained from the KE formula are not units of work? am i correct?

its a take home quiz... the formulas stated are... KE, PE, work, power and %lost

i was hesitant because Joules obtained from the KE formula are not units of work? am i correct?

That is correct, the units of work are Watts; $$W$$, or in other terms:

$$Js^{-1}$$;

$$kg \cdot m^{2} s^{-3}$$;

$$N \cdot ms^{-1}$$

As you can see, all of these units involve a measurement of time, so are you sure there is not mention of time in the question?

edit: you are confusing me haha; the units of work ARE joules, so the work done is the $$E_{k}$$

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well ...

part B of the question says... if the car does this work in a time of 4 seconds, what power did the car develop?
could you use this on part A?