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ehabmozart
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Homework Statement
At the base of a frictionless icy hill that rises at 25 degree above horizontal, a toboggan has a speed of 12m/s toward the hill. How high vertically above the base will it go before stopping?
Homework Equations
WORK ENERGY THEOREM
The Attempt at a Solution
I know the answer but the steps were quite confusing.
W= Delta K. Where W should be the NET work. Weight does a work at 180 from the displacement. So Wmg = -mgh.. Fine! Now, the book equated this with the kinetic energy. Isn't there a normal force acting too. Why didn't the book consider the work done by the normal force. I feel i should add W done by N= (mgcos theta) x cos theta x h ... Why can't i do that... I need good replies. Thanks to whoever contributes with good answers. :)