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## Homework Statement

A .190 kg block is compressing a spring k = 200 N/m for a dist. of .15m. The spring is mounted horizontally and the surface directly under it is frictionless. But beyond the equilibrium position of the spring end, the surface has a coefficient of friction u = .27. The frictional surface extends 85 cm, followed by a frictionless curved rise. After launch where does the block finally come to rest. MEasure from the left end of the frictional zone.

## Homework Equations

## The Attempt at a Solution

Well the first thing I do is find the PE of the spring. PE = .5 k x^2 = 2.25 J

Secondly, I figure out the Work caused the by the frictional patch. W = .190*g*.27*.85 = .427329 J

Then I subtract them 1.82 J and this is where I get stuck, since I don't know the curvature of the curve, how am I supposed to figure out when it comes to rest? I can figure out the velocity at the end of the patch and I can also figure out the height from mgh = 1.82J, but that still doesn't take into account the curve... I've also thought about trying kinematic equations, but that doesn't seem to work either.