- #1

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- Homework Statement
- An electron, having the initial velocity of 10^6 m/s, is approaching from a long distance another electron, which is free and at rest. Calculate the maximum force of interaction between the particles. The answer must be 2.26*10^-10 N

- Relevant Equations
- KE=mv^2/2

F=ke^2/d^2

I tried to make the kinetic energy of the first electron equal to the electric potential work.

mv^2/2=ke^2/d

We have to solve for the minimum distance between them: d=2ke^2/mv^2=5.05*10^-10 m

The force is: F=ke^2/d^2=9*10^-10 N, which is not correct.

mv^2/2=ke^2/d

We have to solve for the minimum distance between them: d=2ke^2/mv^2=5.05*10^-10 m

The force is: F=ke^2/d^2=9*10^-10 N, which is not correct.