# Work on a syringe

1. Jan 31, 2012

### DanicaK

A syringe is filled with water and placed in horizontal position. How much work should we do pressuring the clip with a constant force in order to remove the water from the syringe in a time t. The volume of the water in the syringe is V, the cross-sectional area of the opening is S1 and is very smaller than the area of the cross-section of the clip. Don't take into consideration the friction.

hmm

2. Jan 31, 2012

### Simon Bridge

hmm ... indeed.
So what have you tried?

W=Fd seems a good start - what would d be then?
Pressure exerted on the plunger-end of the water would be F/S1
If the opening were the same as S1 what sort of motion would you expect from the plunger?
How does this change since the opening is "very small"?
Stuff like that? Show me.

Start the hmm problems by playing around with the concepts and something will usually strike a chord with a recent lesson or a related concept.

3. Jan 31, 2012

### DanicaK

p1+ρgh+ρv1^2/2=p2+ρgh+ρv2^2/2
p1=F/A1
we cancel ρgh
p2=p(atm)
ρv1^2/2=0 because the opening is very smal
so, F/A1=p(atm)+ρv2^2/2

A1v1=A2v2

Now I don't know how to use the volume and the time.
And how to find d in order to calculate the work.

4. Jan 31, 2012

### Simon Bridge

volume = area x distance