I am looking at quation 10 but it relates to question 9
In question 9 I calculated the electric feild to be 5.4 X10^6 N/c.
I did this by using the equation E = K(Q/r^2)
The Attempt at a Solution
I would assume that I would use this equation for question 10
W = PE2 - PE1 = -qEd
W = -(1.5x10^-6 C)(5.4 x 10^6 N/c)(0.25m)
W= -2.025 J
The sign is negative because the work is in the opposite direction of the electrical field.
This seems to be too simple. Am I missing something?
Thanks for the help
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