(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

I am looking at quation 10 but it relates to question 9

http://137.186.166.185:8080/question.gif

2. Relevant equations

In question 9 I calculated the electric feild to be 5.4 X10^6 N/c.

I did this by using the equation E = K(Q/r^2)

3. The attempt at a solution

I would assume that I would use this equation for question 10

W = PE2 - PE1 = -qEd

therfore

W = -(1.5x10^-6 C)(5.4 x 10^6 N/c)(0.25m)

W= -2.025 J

The sign is negative because the work is in the opposite direction of the electrical field.

This seems to be too simple. Am I missing something?

Thanks for the help

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# Homework Help: Work on done on a test charge

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