# Work/Parametric Equations

## Homework Statement

A dish, described by the equation x2+z2=ey for 0 < y < 10cm (or equal too) is filled 5cm high with milk. How much work does it take to spill all the milk on the floor? Take milk density to be 1030 Kg/m3 and gravitational acceleration to be 9.8 m/s2.

## Homework Equations

I know that the work formula is
W= int(0 to h): F(y)dy+(T-h)(F(h)), and F(y0)=(dens)(g.acc)(Volume above y0), but I am stuck at the volume part of the equation.
It should be V(y)=int(0 to y): A(y), where the area is Pi(r)2. This is where I get stuck. How do I convert the x2+z2=ey into a radius function? So far, nobody's been able to explain parametrics to me very clearly even with just x and y, but now there's a z variable and I'm just clueless.

## The Attempt at a Solution

I got y=ln(x2+z2) and x=sqrt(ey+z2) so far..

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Dick
Homework Helper
Isn't x^2+z^2=e^y a circle in the x-z plane with radius e^y?

so then is it just the integral of pi(ey)2?

In which case V(y)= Pi((1/2)(e2y)) from 0-5, and a constant Pi((1/2)(e2(5))) from 5-10cm?

Dick
Homework Helper
Yes, the volume is integral of A(y)=pi*(e^y)^2. I'm having a some trouble following the rest the work calculation. T is 10cm, right? So isn't the formula just integral 0 to 5 (g.acc)*(density)*(T-y)*A(y)dy?

Hm.. I'm not entirely sure, I just posted the formula straight off my formula sheet. The first part is the work of moving the varying amount of fluid, and the second just moving it out through the open space in the dish. The force is constant for the (T-h) (10-5cm), but we need to take a second integral for the force of moving the volume as it changes during the emptying. Thats what I understand from my notes, at least. If it helps I just finished the question and got this, basically:

W = (integral(0-.05): 10094pi/2(e2y)) + (.1-.05)(10094pi/2)(e2(.05))

Where the bold is the force to move the milk up until its surface in the dish and the regular face is just the force to move the then-constant volume from the 5cm up to the 10cm. I could be wrong though...

Dick