# Work problem 2

## Homework Statement

71. A paratrooper fell 370 m after jumping from an aircraft without his parachute opening. He landed in a snowbank, creating a crater 1.1 m deep. Assuming the paratrooper's mass was 80 kg and his terminal velocity was 30 m/s, estimate : a) the work done by the snow in bringing him to rest; b) the average force exerted on him by the snow to stop him; c) the work done on him by air resistance as he fell.

A. a) -36000 J , b) -3300 N , c) -250000 J

## Homework Equations

W = mgh = Fdsin$$\theta$$= $$\frac{1}{2}$$mv$$^{2}$$

## The Attempt at a Solution

a) I got a) by using .5mv$$^{2}$$. However, I don't know how to get b) and c)

what's making the paratrooper fall? Force by gravity. So to stop him what force must be applied? Think of newtons third law.

What is work? work is force times distance. The distance is the depth of the crater, what is the work?

PhanthomJay
Homework Helper
Gold Member
Where are these answers coming from? None are correct........

newton's third law is about action and reaction, isn't it?

this is what i did for b)
W = Fdsin$$\theta$$ = 80 * 9.8 * 1.1 = 862.4 Joule

However, this is wrong because my answer is different from the given answers.

PhanthomJay
Homework Helper
Gold Member
newton's third law is about action and reaction, isn't it?

this is what i did for b)
W = Fdsin$$\theta$$ = 80 * 9.8 * 1.1 = 862.4 Joule

However, this is wrong because my answer is different from the given answers.
your answer and the given answers are incorrect. The net work done on the 'trooper in bringing him to rest is his change in KE. The net work includes the work done by the snow and the work done by gravity. Once you calculate the work fone by the snow, then the force of the snow on the trooper can be calculated using the definition of work. Are you familiar with conservation of energy equations? Otherwise, you'll have to use the kinematic equations and newtons laws.

What is work?

$$Work=\int F ds$$

From this you can find that

$$Work=-\Delta U$$ and $$Work=\Delta KE$$