Here is the problem: A 10.0-kg crate is pulled up a rought 20 degree incline by a 100-N force parallel to the incline. The initial speed of the crate is 1.5 m/s, and the coefficient of kinetic friction is 0.40. The crate is pulled a distance of 5.00m. Determine the work done by the: 1. Gravitational force 2. 100-n force 3. Change in KE of the crate 4. What is the speed after it is pulled 5.00m? Here are my answers: 1. W=mgh=167.76 J 2. W=Fdcos(theta)=469.84J 3. KE=KE(f)-KE(i)= 302.085J 4. KE +W=KE(f) + PE(f) v=7.916 m/s Can anybody confirm these answers for me? I only feel half confident on them.