I have question regarding work and I was stuck with the wrong solutions.(adsbygoogle = window.adsbygoogle || []).push({});

A guy slides a crate up a ramp at angle of 27 deg. by exerting a 285 N force parallet to the ramp. The crate moves at a constant spped. The coefficient of friction is 0.23. How much work did this guy do when the crate was raised a vertical distance of 1.27 m?

I started with constant speep. It means that the force 285 N = mg*sin27 + mgcos27*0.23

m = 44.13 kg.

delta U = 44.13 * 9.8 * 1.27 = 549 J

W = - delta U = - 549 J.

The answer was wrong. Can anyone help. Thanks in advance.

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# Homework Help: Work problem

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