(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

67. How fast must a cyclist climb a 6 degrees hill to maintain a power output of 0.25 horse power? Neglect work done by friction and assume the mass of cyclist plus bicycle is 70 kg.

A. 2.6 m/s

2. Relevant equations

W = mgh = Fdsin[tex]\theta[/tex]= [tex]\frac{1}{2}[/tex]mv[tex]^{2}[/tex]

3. The attempt at a solution

(0.25 hp * 735.5 W * 3600 J) = 70 * 9.8 * h * sin(6) = [tex]\frac{1}{2}[/tex]*70v[tex]^{2}[/tex]

661950=71.707h =35v[tex]^{2}[/tex]

I don't get how the answer should be only 2.6 m/s.

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# Homework Help: Work problem

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