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**[SOLVED] Work question please help**

## Homework Statement

An applied force varies with position according to F = k_1x^n − k_2 , where n = 3,

k_1 = 5.6 N/m, and k_2 = 68 N. How much work is done by this force on an object that moves from x_i = 4.56 m to x_f = 7.88 m? Answer in units of kJ.

## Homework Equations

Integral from x_i to x_f of the function

## The Attempt at a Solution

I attempted to take the integral from 4.56 to 7.99 and got 4310.17 but this is not right. I then thought that I had not converted to kJ so i divided by 1000 and got 4.31017 but that is also wrong. I would appreciate any help.