A 2000kg elevator rises from rest in the basemtn to the fourth floor, a distance of 25m. As it passes the fourth floor, its speed is 3.0 m/s. There is a constant frictional force of 500N. Calculate the work done by the lifting mechanism.(adsbygoogle = window.adsbygoogle || []).push({});

I tried doing v2square = v1square + 2ad and i get 0.18 acceleration

plugged that into f=ma

to get force,

did force X distance + (friction X distance)

and im not getting right answer

whcih is 0.5115MJ

any quick solutoins!

thanks

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# Homework Help: Work Question

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