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Work Up an Incline

  1. Oct 22, 2008 #1
    1. The problem statement, all variables and given/known data
    A 50 kg box is being pushed up an incline of 25 degrees, to a total height of 45 m. Kinetic friction between the box and the incline has a mew of .4.
    a) What is the work done by gravity?
    b)What is the work done by friction?
    c) What is the work done by the person pushing the box.



    2. Relevant equations
    W = Fd


    3. The attempt at a solution
    For all of the parts, I am not sure what to use as my d. Do I use 45, or do i use (45/sin(45)), the hypotenuse and the distance that the box actually slides?
     
  2. jcsd
  3. Oct 22, 2008 #2

    LowlyPion

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    For changes in PE it's straight height difference.

    For friction it's distance along the incline.
     
  4. Oct 22, 2008 #3
    What about the work done by gravity? Is that height or distance on the incline? Or does it not matter.
     
  5. Oct 22, 2008 #4

    LowlyPion

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    Work by gravity is change in PE = m*g*h
     
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