(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

One mole of gas is initially at a pressure of 3.9 atm, volume of .29 L and has an internal energy equal to 108.1 J. In its final state the gas is at pressure 1 atm and volume .7 L, and its internal energy equals 169 J. (There are 6 different questions using this data).

For the path IAF, calculate the work done on the gas. Answer in units of J

okay well there is a graph to better visualize the problem but i can't exactly draw it out but basically the path IAF makes a right angle (If you start from point I you go down and then right). I is at 3.9 atm and .29 L, A is at 1 atm and .29 L, and F is at 1 atm and .7 L.

2. Relevant equations

Work = Pressure x Change in Volume

3. The attempt at a solution

Well to start it off, there is no work done from I to A so therefore you only need to find the work from point A to F

W from path A to F= (1 atm)(.41 litres)

convertingggg

W=(101300 N/m^2)(.00041 m^3)

so you should get

41.533 N*m

so

41.533 J

and somehow when i submit that in, it comes at as wrong... help? :uhh:

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# Homework Help: Work using a P-V Graph

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