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Working out a value for H?

  1. Feb 12, 2009 #1
    Working out a value for H!?

    Hi there!

    I'm a new student to physics and i'm still learning a lot about it.
    Our teacher recently gave a question and i'm not sure how to work out the answer, can anyone help me?

    So here it goes:
    Here's a waterfall (See pic), the water at the bottom of the waterfall is 1C hotter than the water at the top of the waterfall.

    How would I work out a value for h?

    Please see picture below for diagram

    [​IMG]

    Any help much appreciated!

    Here is my attempt at solving the problem:

    E = MC (delta) theta

    = (Mass of water) (4200) ( theta + 1)


    --------------------------------------------
    Potential energy = mgh

    = M(9.8)(h)
    --> 9.8mh = 4200 (mass)( theta + 1)

    --> 9.8h = 4200( theta + 1)
     
    Last edited: Feb 12, 2009
  2. jcsd
  3. Feb 12, 2009 #2

    LowlyPion

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    Re: Working out a value for H!?

    Welcome to PF.

    4200 or 4186 the method looks sound.
     
  4. Feb 12, 2009 #3
    Re: Working out a value for H!?

    Right I understand that but I can't seem to get any further than the above.
     
  5. Feb 12, 2009 #4

    LowlyPion

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    Re: Working out a value for H!?

    Sorry I thought you had it.

    Examine then the ΔE which by your equation can be written as

    ΔE = m*C*ΔT

    mgh = mC*ΔT

    gh = C*ΔT

    For a 1° change then

    h = C/g
     
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