Working out a value for H!? Hi there! I'm a new student to physics and i'm still learning a lot about it. Our teacher recently gave a question and i'm not sure how to work out the answer, can anyone help me? So here it goes: Here's a waterfall (See pic), the water at the bottom of the waterfall is 1C hotter than the water at the top of the waterfall. How would I work out a value for h? Please see picture below for diagram Any help much appreciated! Here is my attempt at solving the problem: E = MC (delta) theta = (Mass of water) (4200) ( theta + 1) -------------------------------------------- Potential energy = mgh = M(9.8)(h) --> 9.8mh = 4200 (mass)( theta + 1) --> 9.8h = 4200( theta + 1)
Re: Working out a value for H!? Right I understand that but I can't seem to get any further than the above.
Re: Working out a value for H!? Sorry I thought you had it. Examine then the ΔE which by your equation can be written as ΔE = m*C*ΔT mgh = mC*ΔT gh = C*ΔT For a 1° change then h = C/g