1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Working out a value for H?

  1. Feb 12, 2009 #1
    Working out a value for H!?

    Hi there!

    I'm a new student to physics and i'm still learning a lot about it.
    Our teacher recently gave a question and i'm not sure how to work out the answer, can anyone help me?

    So here it goes:
    Here's a waterfall (See pic), the water at the bottom of the waterfall is 1C hotter than the water at the top of the waterfall.

    How would I work out a value for h?

    Please see picture below for diagram

    [​IMG]

    Any help much appreciated!

    Here is my attempt at solving the problem:

    E = MC (delta) theta

    = (Mass of water) (4200) ( theta + 1)


    --------------------------------------------
    Potential energy = mgh

    = M(9.8)(h)
    --> 9.8mh = 4200 (mass)( theta + 1)

    --> 9.8h = 4200( theta + 1)
     
    Last edited: Feb 12, 2009
  2. jcsd
  3. Feb 12, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    Re: Working out a value for H!?

    Welcome to PF.

    4200 or 4186 the method looks sound.
     
  4. Feb 12, 2009 #3
    Re: Working out a value for H!?

    Right I understand that but I can't seem to get any further than the above.
     
  5. Feb 12, 2009 #4

    LowlyPion

    User Avatar
    Homework Helper

    Re: Working out a value for H!?

    Sorry I thought you had it.

    Examine then the ΔE which by your equation can be written as

    ΔE = m*C*ΔT

    mgh = mC*ΔT

    gh = C*ΔT

    For a 1° change then

    h = C/g
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?