Working out the units?

  • Thread starter tommyboo
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  • #1
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Main Question or Discussion Point

I am having a problem finding the correct SI unitsfor the quantity A?

In the equation

A=√(R/TY)

That is A equals the square root of R divided by TY

(not to good showing workings on the computer sorry)

, the SI units of the quantity R are kg m^3 s^–2, the SI units of the quantity T are kg and the SI units of the quantity Y are m s^–2. What are the correct SI units for the quantity A?
 
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Answers and Replies

  • #2
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I am having a problem finding the correct SI unitsfor the quantity A?

In the equation

A=√R/TY

That is A equals the square root of R divided by TY
Both your notation and explanation are ambiguous.

Is the expression on the right side this?
[tex]\sqrt{\frac{R}{TY}}[/tex]
or this?
[tex]\frac{\sqrt{R}}{TY}[/tex]
(not to good showing workings on the computer sorry)

, the SI units of the quantity R are kg m^3 s^–2, the SI units of the quantity T are kg and the SI units of the quantity Y are m s^–2. What are the correct SI units for the quantity A?
 
  • #3
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The first one R/ty all square root. Do apologise for the bad format
 
  • #4
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Then, the units of A are meters.
 
  • #5
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To clarify gsal's answer...

You have the expression
[tex]\sqrt{\frac{R}{TY}}[/tex]

Simply, insert the units for each variable (in place of the variables):
[tex]\sqrt{\frac{\frac{kg\cdot m^3}{s^2}}{(kg)(\frac{m}{s^2})}}[/tex]

and simplify...
[tex]\sqrt{\left(\frac{kg \cdot m^3}{s^2}\right) \left(\frac{s^2}{kg \cdot m}\right)}[/tex]

kg and s2 cancel out, leaving
[tex]\sqrt{\frac{m^3}{m}}[/tex]

which is
[tex]\sqrt{m^2}[/tex]

or, more simply m
 

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