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I have to work this problem 3 ways, and I've gotten two, but am not sure about the third way.
integral (x/sqrt(x^2-9))dx
the first way I worked by setting u = x^2 - 9
the second way I worked by setting x = 3sec(theta)
but the third way I have no clue, the book gave us a hint: Let x^2 - 9 = (sin(theta))^2
Thanks
integral (x/sqrt(x^2-9))dx
the first way I worked by setting u = x^2 - 9
the second way I worked by setting x = 3sec(theta)
but the third way I have no clue, the book gave us a hint: Let x^2 - 9 = (sin(theta))^2
Thanks