- #1

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the teams are say equally likely to win any one game

what is the probability that the series will last exactly four games?

five games? six games? seven games?

if i know 4 i could figure out 5 6 and 7 of course

thanks

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- Thread starter blumfeld0
- Start date

- #1

- 148

- 0

the teams are say equally likely to win any one game

what is the probability that the series will last exactly four games?

five games? six games? seven games?

if i know 4 i could figure out 5 6 and 7 of course

thanks

- #2

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- #3

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~Lyuokdea

- #4

vsage

(W is win, L is lose)

WWWLW

WWLWW

WLWWW

LWWWW so there are four ways. Note that this is 5!/(4!*1!) - 1

How about 6 games or 7 games? It would probably be easiest to write down all the possibilities unless you see a pattern going on.

- #5

Curious3141

Homework Helper

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You can make similar analogies for 5,6,7.

- #6

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EDIT: Bad method, it was much more confusing than it needed to be. I'll just remove it to prevent confusion. Follow Curious's advice. Sorry.

~Lyuokdea

~Lyuokdea

Last edited:

- #7

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(4,4) * .5^4 * .5 ^(4-4)= .5^4 = .0625

right?

now for five games there are four ways to win like vsage said

so is that just

4* .5^4 = .25?

then for six games there are 14 ways to win i think (because 6!/(2!*4!)-1=14) so

14*.5^4 = .875

opps wait probability cant be larger then one and it already im so confused

anyone have a solution for 5 6 and 7?

seems so basic but so hard

- #8

Curious3141

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blumfeld0 said:ok so for 4 games i think it is just

(4,4) * .5^4 * .5 ^(4-4)= .5^4 = .0625

right?

I think you should multiply by two because EITHER Team A OR Team B could win 4 games in a row. Which is why when I made the analogy to the coin toss, I said 4 heads OR 4 tails.

The answer for 4 in a row = 1/8.

- #9

vsage

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