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Would i use the fundamental counting principal or is this a permutation

  1. May 23, 2005 #1
    thare are 8 candidates for three student seats how many different ways can the seats be chosen? With the FCP I get 24 If it is a permutation I get 336 which is right and why? Thanks for the help
     
  2. jcsd
  3. May 23, 2005 #2
    336 is correct. If candidate 1 takes the first seat, you have 7 candidates to take seat two, and for each of the seven candidates you have 6 more to take seat three. So whichever of the candidates takes the first seat gives 42 possibilities for the remaining candidates to take the other. 42 * 8 = 336.
     
  4. May 23, 2005 #3
    or 8 permutate 3. (8*7*6 as stated above)
     
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