- #1
WehrdScience
- 6
- 0
So I have asked a few wrench questions and bolt questions, now to tie them together (figuratively). Please excuse my variables if they do not match your own. Do I understand that the Ideal Mechanical Advantage of a wrench is like a wheel and axle system where:
IMA = radius (wrench) / radius (bolt)
...and the Ideal Mechanical Advantage of a bolt is also similar to a wheel and axle, but also a screw too where:
IMA = diameter (bolt) / thread pitch (bolt)
And Torque (Work) of the wrench would be:
T = force * distance => force applied to the wrench in Newtons multiplied by the distance of end of wrench from the bolt (radius in (lets say) meters)
But is there not also Torque (Work) of the bolt? Where:
T = force * distance => force applied to the bolt in Newtons multiplied by the distance of bolt (radius in again, meters (to keep the units the same).
BUT, neglecting friction or lubrication or material specifications, shouldn't the work or torque we put into the wrench EQUAL the work or torque onto the bolt? So that:
F(wrench) * d(wrench) = F(bolt) * d(bolt) ?
Where would the mechanical advantage come into play? It seems there are really two problems here...one for the wrench...and one for the bolt.
1) Bottom line...I would like to see a formula that if I know what FORCE I input onto a wrench of X radius...it will tell me the FORCE and TORQUE of the bolt...
2) Also, is the torque calculated in #1 on the head of the bolt or on the end of the bold pressing into the material behind it or both? Because I need the force or torque or pressure (ANYTHING will do and I can convert it backwards or forwards) of the END of the bolt...
Thank you for helping me...it may seem simple to you, but it has been driving me crazy for weeks! I have every measurement needed to make this happen, but please use convenient numbers to help explain these questions.
Thank you all so much, I really appreciate this forum!
-WehrdScience
IMA = radius (wrench) / radius (bolt)
...and the Ideal Mechanical Advantage of a bolt is also similar to a wheel and axle, but also a screw too where:
IMA = diameter (bolt) / thread pitch (bolt)
And Torque (Work) of the wrench would be:
T = force * distance => force applied to the wrench in Newtons multiplied by the distance of end of wrench from the bolt (radius in (lets say) meters)
But is there not also Torque (Work) of the bolt? Where:
T = force * distance => force applied to the bolt in Newtons multiplied by the distance of bolt (radius in again, meters (to keep the units the same).
BUT, neglecting friction or lubrication or material specifications, shouldn't the work or torque we put into the wrench EQUAL the work or torque onto the bolt? So that:
F(wrench) * d(wrench) = F(bolt) * d(bolt) ?
Where would the mechanical advantage come into play? It seems there are really two problems here...one for the wrench...and one for the bolt.
1) Bottom line...I would like to see a formula that if I know what FORCE I input onto a wrench of X radius...it will tell me the FORCE and TORQUE of the bolt...
2) Also, is the torque calculated in #1 on the head of the bolt or on the end of the bold pressing into the material behind it or both? Because I need the force or torque or pressure (ANYTHING will do and I can convert it backwards or forwards) of the END of the bolt...
Thank you for helping me...it may seem simple to you, but it has been driving me crazy for weeks! I have every measurement needed to make this happen, but please use convenient numbers to help explain these questions.
Thank you all so much, I really appreciate this forum!
-WehrdScience