- #1

gravenewworld

- 1,132

- 26

How can one write any natural number n in one and only one way as 1 less than a power of 2 times an odd number?

n=2^f(n)(2g(n)-1)-1

where the red minus is the modified difference function, i.e. x-y =x-y if x>=y or x-y=0 if x<y

n=2^f(n)(2g(n)-1)-1

where the red minus is the modified difference function, i.e. x-y =x-y if x>=y or x-y=0 if x<y

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