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Wronskians equations help

  • Thread starter Gogeta007
  • Start date
  • #1
23
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Im doing my Differential Equation's homework, and I've come across some really hard problems, when it got really complicated I tuoght i was wrong (you know book's problems tend to workout nicely) . . .anyways I got REALLY stuck on this one if anyone can guide me thank you

Homework Statement



y''+3y'+2y = 1/(1+ex)

Homework Equations



Use variation of parameters (the chapter is about wronskians)

The Attempt at a Solution



first we find the complementary equation using the auxiliary equation (m2+3m+2) and find that
yc=c1e-2x + c2e-x

therefore y_1=e^-2x and y_2=e^-x

then we use the Wronskian of
| y_1 y_2 |
| y'_1 y'_2 | = -e^-3x - ( -2e^-3x) therefore W= e^-3x

W_1= using f(x) = 1/(1+e^x)

| 0 y_2 |
| f(x) y'_2 | = 1 / (e^x+e^2x) = u'

to find yp=u1y1 + u2y2

the problem is finding u, since the u' = W_1/W . . .which would yield

e^3x / (e^x+e^2x)


I would have to integrate that, I cant find anyway to do it, I tried integration by parts and partial fraction decomposition.
I was thinking of looking it up in an integration table. But since its a problem from the book (and the book doesnt have an integration table) I dont think the book is THAT demanding as in to go look it up in another book.
Im thinking maybe im doing something wrong. . .


==
Thank you!
 

Answers and Replies

  • #2
201
0


e^3x / (e^x+e^2x) is basically e^2x/(1+e^x), right?

did you try integration by parts ?
or first do u=e^x
and see if it helps
 

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