#### khalid_kacst

**x^2 - y^2 = x - y , ?????**

if y not equal x .

what is y and x when

x^2 - y^2 = x - y

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- Thread starter khalid_kacst
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if y not equal x .

what is y and x when

x^2 - y^2 = x - y

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You get:

x = 1; y = 1;

(1)^2 - (1)^2 = (1) - (1)

==> 0 = 0

Gold Member

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he asked for solution in which x doesnt equal y.Originally posted by renedox

You get:

x = 1; y = 1;

(1)^2 - (1)^2 = (1) - (1)

==> 0 = 0

now i know it's simple but the question seems to be simple

x^2-y^2=x-y

(x-y)*(x+y)=x-y /x-y

x+y=1

now for positive integers it could only be x=0 y=1 or the opposite, the other solutions are negative integers and positive ones.

btw, can someone explain how is this a question about calculus?

Science Advisor

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Gah, don't be tired and browes PF at the same time :POriginally posted by loop quantum gravity

he asked for solution in which x doesnt equal y.

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use implicit differentiation and find the derivative

Science Advisor

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What has this got to do with it???????use implicit differentiation and find the derivative

I also wonder the same , and how is that will be useful ?

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