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X^2+y^2+z^2=nxyz n is natural

  1. Dec 7, 2008 #1
    can any one give solution to this quation
    x^2+y^2+z^2=nxyz n is natural
  2. jcsd
  3. Dec 7, 2008 #2


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    Re: equation

    (x, y, z, n) = (1, 1, 1, 3)
  4. Dec 14, 2008 #3
    Re: equation

    The answer is described ad a hyper-surface of dimension 2 except if you are talking about a diophantic equation over the integers, please be more especific.
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