- #1

- 383

- 2

^{2}+ y

^{2}if x and y are positive integers and

xy + x + y = 71

xy(x + y) = 880

this is what i have done:

since x and y divides 880, x or y must be 2, 5 or 11, because 880 = 2

^{4}.5.11

from the first equation i can see that

x = 11 and y = 5 or x = 5 and y = 11

so x

^{2}+ y

^{2}= 146

**but is there a way to do it algebraically?**

thanks in advance.